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use go built-in min & max functions to replace lo.Min and lo.Max (#4007)

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fatedier 2024-02-19 21:27:56 +08:00 committed by GitHub
parent adb04e81e7
commit b6361fb143
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2 changed files with 4 additions and 4 deletions
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2
pkg/nathole/analysis.go
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@ -224,7 +224,7 @@ func (mhr *MakeHoleRecords) ReportSuccess(mode int, index int) {
}
score.Score += 2
score.Score = lo.Min([]int{score.Score, 10})
score.Score = min(score.Score, 10)
return
}
}

6
pkg/nathole/controller.go
View File

@ -317,7 +317,7 @@ func (c *Controller) analysis(session *Session) (*msg.NatHoleResp, *msg.NatHoleR
session.cBehavior = cBehavior
session.vBehavior = vBehavior
timeoutMs := lo.Max([]int{cBehavior.SendDelayMs, vBehavior.SendDelayMs}) + 5000
timeoutMs := max(cBehavior.SendDelayMs, vBehavior.SendDelayMs) + 5000
if cBehavior.ListenRandomPorts > 0 || vBehavior.ListenRandomPorts > 0 {
timeoutMs += 30000
}
@ -384,8 +384,8 @@ func getRangePorts(addrs []string, difference, maxNumber int) []msg.PortsRange {
return nil
}
ports = append(ports, msg.PortsRange{
From: lo.Max([]int{port - difference - 5, port - maxNumber, 1}),
To: lo.Min([]int{port + difference + 5, port + maxNumber, 65535}),
From: max(port-difference-5, port-maxNumber, 1),
To: min(port+difference+5, port+maxNumber, 65535),
})
return ports
}